tag:blogger.com,1999:blog-5465015914589377788.post2188143530231965993..comments2020-09-21T10:31:05.604-04:00Comments on Michael James on Money: Short Takes: Defined-Benefit Pensions and moreMichael Jameshttp://www.blogger.com/profile/10362529610470788243noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-5465015914589377788.post-52920890201228534652012-05-16T13:03:57.605-04:002012-05-16T13:03:57.605-04:00Thank you so much for your math expertise and your...Thank you so much for your math expertise and your quick reply. <br /><br />No it wasn't homework. At my regular poker game the other night, a player offered anyone a side bet on each hand played where he would take the 3, 6 & 9. If any of those cards came up on the flop you had to pay him a $1, if none of them came up he had to pay you a $1. Although at first blush it appears it is a good bet to take, I figured there was no way he would offer the bet if he didn't have the advantage, so I didn't take his bet, but was curious afterwards how much his advantage would have been. After seeing your math, which proves he had a 55% chance of winning each flop, I'm glad I didn't take the bet.<br /><br />Sorry for my delayed thank you, as I forgot I asked the question, and just remembered to go back into the comments for this post to see if you had answered.Jeff Gnoreply@blogger.comtag:blogger.com,1999:blog-5465015914589377788.post-89190494298511465782012-05-13T10:27:16.240-04:002012-05-13T10:27:16.240-04:00Thanks for the mention Michael.
I heard they are...Thanks for the mention Michael. <br /><br />I heard they are replacing Tobey Maguire as Spiderman for the next trilogy, fyi.WhereDoesAllMyMoneyGo.comhttps://www.blogger.com/profile/09185007666460707356noreply@blogger.comtag:blogger.com,1999:blog-5465015914589377788.post-67055610338772273582012-05-11T14:38:08.619-04:002012-05-11T14:38:08.619-04:00@Jeff G: This isn't a homework question, is i...@Jeff G: This isn't a homework question, is it? :-)<br /><br />For questions lie this, it's easier to work out the probability of not getting at least one of 12 cards in 3 tries. This is just<br /><br />(40/52)*(39/51)*(38/50)<br /><br />Then take 1 minus this probabiity.Michael Jameshttps://www.blogger.com/profile/10362529610470788243noreply@blogger.comtag:blogger.com,1999:blog-5465015914589377788.post-76999594255738056622012-05-11T13:31:50.394-04:002012-05-11T13:31:50.394-04:00Love your blog - I check it first thing every morn...Love your blog - I check it first thing every morning.<br /><br />This isn't a personal finance question, but I'm guessing you'd be able to figure out a finite question that has been bothering me, so I'll throw it out there and see if you'd like to.<br /><br />How would I calculate the odds of at least one 3, 6 or 9 coming up if I randomly drew three cards from a deck of playing cards?<br /><br />I figure if it was just one card being pulled from the deck, it would 12/52 or a 23% chance, but I can't figure out how much the percentage increases with 3 cards being pulled from the deck.Jeff Gnoreply@blogger.comtag:blogger.com,1999:blog-5465015914589377788.post-75624235212253784152012-05-11T06:00:11.081-04:002012-05-11T06:00:11.081-04:00If I could figure out how to make an origami penis...If I could figure out how to make an origami penis out of the cheques and send them back to whomever sent them, I would, but that would take too darn long!Big Cajun Manhttp://canajunfinances.comnoreply@blogger.com